Kensington Gentle Care Home, located in Saskatoon, SK S7L 6M9. The company is currently looking for applications for the role of Food service supervisor. We are seeking a self-disciplined individual with exceptional interpersonal skills. The chosen applicant will be required to join and begin their duties as soon as possible. The open positions are for Permanent employment or full-time jobs. The candidate must be available to work early morning, morning, day, night, and weekend shifts, as well as on a shift basis, and be available on call.
Employer Name: Kensington Gentle Care Home
Position: Food service supervisor
No. of vacancies: 1
Salary: $34.00 hourly / 30 to 40 hours per week
Employment type: Permanent employment, Full-time
Location: Saskatoon, SK S7L 6M9
Also hiring: Post Office Assistant
Job Description
- The candidate will be responsible for supervising and coordinating the activities of staff who prepare and portion food.
- The candidate must train staff on job duties, sanitation, and safety procedures.
- The candidate must estimate the ingredients and supplies needed for meal preparation.
- The candidate will be responsible for hiring food service staff.
- The candidate must ensure that the food and service meet quality control standards.
- The candidate will be responsible for maintaining records of stock, repairs, sales, and waste.
- The candidate must prepare food order summaries for the chef.
- The candidate must establish work schedules.
Job Requirements
- The candidate should be fluent in the English language.
- The candidate must have a certificate of Secondary (high) school graduation.
- The ideal candidate will have at least 1 to 2 years of experience in a related industry.
How to Apply
To submit your application, please use the given options if you are interested in applying.
In person
202 Stromberg Crt
Saskatoon, SK
S7L 6M9
Between 02:00 p.m. and 03:30 p.m.